A lens that has a focal length of 5.37 cm is used as a magnifying glass. (a) To obtain maximum magnification and an image that can be seen clearly by a normal eye, where should the object be placed?

(b) What is the magnification?

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+2 votes

Part A:

The thin lens equation is:

**1/p + 1/q = 1/f ** (where p=object distance, q=image distance, f=focal length)

To obtain maximum magniﬁcation, the image should be located at the near point of the eye which, for a normal eye, is 25 cm (so **q** = −25.0 cm)

solving for p you get:

**1/p = ****1/f - ****1/q **

**p = 1 / ( ****1/f - ****1/q )**

plug in your values for **f **and** q = -25 cm** to solve.

Part B:

Plug in q and p from above into the magnification equation and solve:

**M = -q / p**

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