A lens that has a focal length of 5.37 cm is used as a magnifying glass.

+2 votes

A lens that has a focal length of 5.37 cm is used as a magnifying glass. (a) To obtain maximum magnification and an image that can be seen clearly by a normal eye, where should the object be placed?
cm from the lens

(b) What is the magnification?

asked Apr 22, 2012 in Physics by swhite5 (68 points)
    

1 Answer

+2 votes

 

Part A:

The thin lens equation is:

1/p + 1/q = 1/f       (where p=object distance, q=image distance, f=focal length)

 

 

To obtain maximum magnification, the image should be located at the near point of the eye which, for a normal eye, is 25 cm (so q = −25.0 cm)
 

solving for p you get:

1/p = 1/f - 1/q 

p = 1 / ( 1/f - 1/q )

plug in your values for and q = -25 cm to solve.

 

Part B:


Plug in q and p from above into the magnification equation and solve:

M = -q / p

 

 

answered Apr 24, 2012 by Gummmys ~Expert~ (1,105 points)



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