# What is the phase angle between the current and the applied voltage?

An RLC circuit consists of a 180  resistor, a 21.0 µF capacitor, and a 400 mH inductor, connected in series with a 120 V, 60.0 Hz power supply.

(a)What is the phase angle between the current and the applied voltage?
°
(b)Which reaches its maximum earlier, the current or the voltage?

asked Mar 19, 2012 in Physics

The phase angle is the angle between the current and voltage.

This is found by using the following formula:

Phase angle = inverse tangent( (XL - XC )/ R)     (*where XL = inductive reactance, XC = capacitive reactance)

So first we need to find XL and XC :

XL = ω*L      (*where ω = angular frequency, L = inductance)

XC = 1 / ω*C     (*where ω = angular frequency, C = capacitance)

and ω is equal to:

ω = 2*pi*f    (*where f = frequency in Hz)

After finding XL and XC, plug back into first equation fo find teh phase angle

Part B:

If XL > XC then Voltage leads,  if XL < XC then Current leads, if they're equal then the phase angle is 0.

answered Mar 25, 2012 by ~Expert~ (3,020 points)
first answer is angle 7.7 second answer is volage
answered May 1, 2013 by anonymous

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