The maxium voltage between each set of point can be established using Ohm's Law:

**Vmax' = Imax * R** (*where Vmax' = max voltage between the points and **not** the same as the Vmax given in question, Imax = max current, R = resistance )

So first we need to find **Imax **before going any further:

**Imax = Vmax / Z** (*where Imax = max current, Vmax = max voltage of source, which is given in question, Z = impedance)

So no we need to find **Z**:

**Z = ****√R^2 + (XL - XC)^2 **** **(*where R = resistance, XL = inductive reactance, XC = capactive reactance)

Now we need to find **XL **and **XC **:

**XL = ω*L** (*where ω = angular frequency, L = inductance)

**XC = 1 / ****ω*C** (*where ω = angular frequency, C = capacitance)

and ω is equal to:

**ω = 2*pi*f** (*where f = frequency in Hz)

After solving for XL and XC, you can then solve for Z.

Next after solving for Z, you can find Imax

Now that you have Imax, you can proceed to use

**Vmax' = Imax * R**

where R is resistance between each est of points.

For example Resistance between points a and b is 40 ohm,

between b and c is **XL**

between c and d is **XC**

For Part D, the voltage between points b and d is the voltage in part B minus the voltage in Part C