A certain lightbulb is rated at 60.0 W when operating at an rms voltage of 120 V.

+2 votes

A certain lightbulb is rated at 60.0 W when operating at an rms voltage of 120 V.

(a) What is the peak voltage applied across the bulb?
 V

(b) What is the resistance of the bulb?
 Ω

(c) Does a 100-W bulb have greater or less resistance than a 60-W bulb?
    

Explain. 

 

asked Mar 19, 2012 in Physics by Gummmys ~Expert~ (1,105 points)
    

1 Answer

+3 votes
 
Best answer

Part A:

Peak Voltage (also known as max Voltage) is given by:

Vmax = Vrms * 2

 

Part B:

You can solve for the resitance by relating power with voltage and resistance:

Power = Vrms^2 / Resistance  

 

Part C:

a 100-W bulb has less resistance than a 60-W bulb, looking at the equation for power, less resistance equals greater power for the same amount of voltage.

answered Mar 23, 2012 by kirby ~Expert~ (3,020 points)
selected Mar 27, 2012 by Gummmys



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