# When an AC source is connected across a 11.5-Ω resistor, the rms current in the resistor is 7.12 A.

When an AC source is connected across a 11.5-Ω resistor, the rms current in the resistor is 7.12 A.

(a) Find the rms voltage across the resistor.
V

(b) Find the peak voltage of the source.
V

(c) Find the maximum current in the resistor.
A

(d) Find the average power delivered to the resistor.
W
asked Mar 19, 2012 in Physics

Part A:

The rms voltage is simply given as:

Vrms = I*R  (*where Vrms= rms voltage, I=current, R=resistance)

Part B:

Peak voltage, is the same as max voltage, which is given by:

Vmax = Vrms * 2

Part C:

Similarily, max current is:

Imax = Irms * 2    (*where Imax = max current, Irms = rms current, which is given in question)

Part D:

There are mulitple ways to find max power using Ohm's Law:

either:

Max Power = Irms^2 * R

or

Max Power = Irms * Vrms

will both give the same answer

answered Mar 20, 2012 by ~Expert~ (919 points)
selected Mar 24, 2012 by Gummmys

## Related questions

1 answer 2,597 views
2,597 views
+1 vote
0 answers 631 views
631 views