When the solenoid carries a current of 0.700 A, how much energy is stored in its magnetic field?

+3 votes

An air-core solenoid with 66 turns is 8.00 cm long and has a diameter of 1.20 cm. When the solenoid carries a current of 0.700 A, how much energy is stored in its magnetic field?
 µJ

asked Mar 6, 2012 in Physics by Joey33 ~Expert~ (1,216 points)
    

1 Answer

+1 vote

Energy of Inductor is given by the formula:

Energy = (1/2) * L*I^2   (*where L=inductance, I=current)

Before we can determine the energy, we need to find L

L = (permeability of free space * N^2 * A) / l (*where N=number turns, A=area = pi*r^2, l=length)

After solving for L, you can then plug back into the first equation to solve for energy.

 

answered Mar 14, 2012 by pokemonmaster ~Expert~ (3,856 points)



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