An air-core solenoid with 66 turns is 8.00 cm long and has a diameter of 1.20 cm. When the solenoid carries a current of 0.700 A, how much energy is stored in its magnetic field?

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+1 vote

Energy of Inductor is given by the formula:

**Energy = (1/2) * L*I^2 **(*where L=inductance, I=current)

Before we can determine the energy, we need to find **L**

**L = (permeability of free space * N^2 * A) / l **(*where N=number turns, A=area = pi*r^2, l=length)

After solving for **L, **you can then plug back into the first equation to solve for energy.

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