Part A:

The power being supplied by the battery is simply

**P = VI **(*where P=power, V=voltage, I=current)

First you need to find current which is

**I = V/R **(*where I=current, V=voltage, R=resistance)

plugging back into the first formula you get power being supplied by the battery

Part B:

The current being delivered to the resistor can be found with

**P = I^2 *R**

which gives the power lost across any compenent of the circuit.

using the same I and R as ealier you can calculate the power being delivered to the resistor.

Part C:

Similarily use

**P = I^2 *R**

however, the resistance across the inductor is 0

so the power would also equal 0.

Part D:

The energy stored in the magnetic field of the inductor is given by the formula:

**U = (1/2)*L*I^2 **(*where U=energy, L=inductance, I=current)