After the current in the circuit has reached its maximum value, calculate the following.

9.9-V battery, a 4.99-Ω resistor, and a 10.6-H inductor are connected in series. After the current in the circuit has reached its maximum value, calculate the following.

(a) the power being supplied by the battery
W

(b) the power being delivered to the resistor
W

(c) the power being delivered to the inductor
W

(d) the energy stored in the magnetic field of the inductor
J
asked Mar 6, 2012 in Physics

+1 vote

Part A:

The power being supplied by the battery is simply

P = VI  (*where P=power, V=voltage, I=current)

First you need to find current which is

I = V/R   (*where I=current, V=voltage, R=resistance)

plugging back into the first formula you get power being supplied by the battery

Part B:

The current being delivered to the resistor can be found with

P = I^2 *R

which gives the power lost across any compenent of the circuit.

using the same I and R as ealier you can calculate the power being delivered to the resistor.

Part C:

Similarily use

P = I^2 *R

however, the resistance across the inductor is 0

so the power would also equal 0.

Part D:

The energy stored in the magnetic field of the inductor is given by the formula:

U = (1/2)*L*I^2    (*where U=energy, L=inductance, I=current)

answered Mar 14, 2012 by ~Expert~ (3,856 points)
selected Mar 14, 2012 by Joey33

+1 vote