After the current in the circuit has reached its maximum value, calculate the following.

+3 votes

9.9-V battery, a 4.99-Ω resistor, and a 10.6-H inductor are connected in series. After the current in the circuit has reached its maximum value, calculate the following.

(a) the power being supplied by the battery
 W 

(b) the power being delivered to the resistor
 W 

(c) the power being delivered to the inductor
 W 

(d) the energy stored in the magnetic field of the inductor
 J
asked Mar 6, 2012 in Physics by Joey33 ~Expert~ (1,216 points)
    

1 Answer

+1 vote
 
Best answer

Part A:

The power being supplied by the battery is simply

P = VI  (*where P=power, V=voltage, I=current)

First you need to find current which is

I = V/R   (*where I=current, V=voltage, R=resistance)

plugging back into the first formula you get power being supplied by the battery

 

Part B:

The current being delivered to the resistor can be found with

P = I^2 *R

which gives the power lost across any compenent of the circuit.

using the same I and R as ealier you can calculate the power being delivered to the resistor.

 

Part C:

Similarily use

P = I^2 *R

however, the resistance across the inductor is 0

so the power would also equal 0.

 

Part D:

The energy stored in the magnetic field of the inductor is given by the formula:

U = (1/2)*L*I^2    (*where U=energy, L=inductance, I=current)

 

 

answered Mar 14, 2012 by pokemonmaster ~Expert~ (3,856 points)
selected Mar 14, 2012 by Joey33

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