When t = 2.00 s, calculate the magnitude of the force exerted on an electron located at point P1, which is at a distance r1 = 5.70 cm from the center of the circular field region. - AnswerMenu

When t = 2.00 s, calculate the magnitude of the force exerted on an electron located at point P1, which is at a distance r1 = 5.70 cm from the center of the circular field region.

+5 votes

Within the green dashed circle shown in the figure below, the magnetic field changes with time according to the expression B = 7.00t^{3} − 2.00t^{2} + 0.800, where B is in teslas, t is in seconds, and R = 2.85 cm.

(a) When t = 2.00 s, calculate the magnitude of the force exerted on an electron located at point P_{1}, which is at a distance r_{1} = 5.70 cm from the center of the circular field region. N

(b) When t = 2.00 s, calculate the direction of the force exerted on an electron located at point P_{1}, which is at a distance r_{1} = 5.70 cm from the center of the circular field region.

clockwisecounterclockwiseThe magnitude is zero.

(c) At what instant is this force equal to zero? s

Thanks for catching this, The 2pi*r is actually the ds part of (E*ds), I had divided it over to the other side of the equation combined it with the A term, I have edited the answer to make it more clear.