From the prompt we know that:
radius of upper circle = 4.00 cm = 0.04 m
radius of lower circle = 8.00 cm = 0.08 m
λ = 4.00 Ω/m
DB/dt = 1.50 T/s
We can eventually solve this using Ohm's Law, but first we should find the values of V and R.
Magnetic Flux = A * B = (pi*(r^2 of upper loop)-pi*(r^2 of lower loop)*B
From Ampere's Law:
E = (dΦB)/(dt) = (pi*(r^2 of upper loop)-pi*(r^2 of lower loop) DB/dt
The resistance for the whole figure is:
R = λ (2 *pi * r of lower loop + 2 * pi * r of upper loop)
Now, with Ohm's Law (E = V = IR) we can plug in our vales and move them around to solve for I (I = V/R).
I = (V/R) = ((pi*(r^2 of upper loop)-pi*(r^2 of lower loop) DB/dt)/ λ (2 *pi * r of lower loop + 2 * pi * r of upper loop)
I = (V/R) = (((r^2 of upper loop)-(r^2 of lower loop) DB/dt)/ (λ * 2 (r of lower loop + r of upper loop)))
Plug in your values and you should have the answer in units Amps. From this the direction of the current should also be counterclockwise in the bottom, and so then also clockwise in the top since it has made a figure 8 shape.