Three negative point charges lie along a line as shown in the figure. Find the magnitude and direction of the electric field this combination of charges produces at point P, which lies 6.00 cm from the -2.00 microC charge measured perpendicular to the line connecting the three charges.

I've used the Pythagorean theorem to find the d for the outside two electric fields, E1 and E2. And I know the y components cancel out because the charges are negative and counteract. I've also converted the cm to m and the microCoulombs to Coulombs.

Here's what I have:

E1 = (8.99x10^9)(-2x10^-5)/(.06m)^2 = 4994.44 N/C

E2 = (8.99x10^9)(-5x10^-6)/(.1m)^2 = 4495000 N/C x cos 53.1 = 4.495 x 10^6

E3 = (8.99x10^9)(-5x10^-6)/(.1m)^2 = 4495000 N/C x cos 53.1 = 4.495 x 10^6

Adding up the Y vectors, I got 5.40 x 10^6; but this answer is wrong. I've been told that it needs to be some number x 10^7, but I have no idea what I'm doing wrong. Could someone please show me with steps what I'm doing wrong? It would really be helpful!

I've used the Pythagorean theorem to find the d for the outside two electric fields, E1 and E2. And I know the y components cancel out because the charges are negative and counteract. I've also converted the cm to m and the microCoulombs to Coulombs.

Here's what I have:

E1 = (8.99x10^9)(-2x10^-5)/(.06m)^2 = 4994.44 N/C

E2 = (8.99x10^9)(-5x10^-6)/(.1m)^2 = 4495000 N/C x cos 53.1 = 4.495 x 10^6

E3 = (8.99x10^9)(-5x10^-6)/(.1m)^2 = 4495000 N/C x cos 53.1 = 4.495 x 10^6

Adding up the Y vectors, I got 5.40 x 10^6; but this answer is wrong. I've been told that it needs to be some number x 10^7, but I have no idea what I'm doing wrong. Could someone please show me with steps what I'm doing wrong? It would really be helpful!