A ball of mass 0.198 kg with a velocity of 1.40 m/s meets a ball of mass 0.304 kg with a velocity of -0.404 m/s in a head-on, elastic collision.

+1 vote

A ball of mass 0.198 kg with a velocity of 1.40 ihatbold m/s meets a ball of mass 0.304 kg with a velocity of -0.404 ihatbold m/s in a head-on, elastic collision.


(a) Find their velocities after the collision.

varrowbold1f =  mark m/s
varrowbold2f =  m/s


asked Oct 25, 2011 in Physics by NoLife ~Rookie~ (87 points)

1 Answer

0 votes
m1 = 0.198kg, m2 = 0.304kg, v1i=1.40 m/s, v2i=-0.404 m/s

v1f=? v2f=?

So according to conservation of momentum final momentum equals initial momentum so:

m1*v1i+m2*v2i = m1*v1f+m2*v2f

when you plug in variables you'll be left with 2 unknowns, therefore you  need one more equation to solve.

Since the collision is ellastic, use this formula:

(v1i-v2i) = v2f-v1f

solve for one variable and plug back into the other equation and solve.

then plug back into the equation to get the second variable.
answered Oct 25, 2011 by pokemonmaster ~Expert~ (3,856 points)

Related questions