Calculate the radius of the path for a singly charged ion having a mass m = 2.60 10-26 kg.

+2 votes

Consider the mass spectrometer shown schematically in the figure below. The magnitude of the electric field between the plates of the velocity selector is 2.80 image 103 V/m, and the magnetic field in both the velocity selector and the deflection chamber has a magnitude of

0.030 0 T. Calculate the radius of the path for a singly charged ion having a mass m = 2.60 image 10-26 kg.
m
image

 

asked Feb 19, 2012 in Physics by Joey33 ~Expert~ (1,216 points)
    

1 Answer

+3 votes
 
Best answer
E=2.80x10^3 V/m

B=0.030 T

m=2.60x10^-26 kg

q=1.60x10^-19 c

 
V=E/B=(2.80x10^3 V/m)/(0.030T)= 9.33x10^4 m/s

r=mV/qB=[(2.60x10^-26 kg)(9.33x10^4m/s)]/[(1.60x10^-19c)(0.030 T)]= .5054 m
answered Feb 25, 2012 by swhite5 (68 points)
selected Feb 25, 2012 by Joey33

Related questions

+2 votes
1 answer 818 views



...