# The magnitude of the net force exerted in the x direction on a 2.35-kg particle varies in time as shown in the figure below.

The magnitude of the net force exerted in the x direction on a 2.35-kg particle varies in time as shown in the figure below.

(a) Find the impulse of the force over the 5.00-s time interval.
= N · s

(b) Find the final velocity the particle attains if it is originally at rest.
f = m/s

(c) Find its final velocity if its original velocity is -3.30 m/s.
f = m/s

(d) Find the average force exerted on the particle for the time interval between 0 and 5.00 s.
avg = N
asked Oct 23, 2011 in Physics

Part a would just be the area under the curve, because I=N*s, and the graph is of newtons and seconds.

and the other parts can be solved using impulse momentum theorem.

net Impulse=change in momentum

and momentum=mass*velocity, using this information you should be able to solve for the other parts.
answered Jan 9, 2012 by ~Expert~ (1,318 points)
edited Jan 9, 2012 by Roar3215