An electron moves in a circular path perpendicular to a constant magnetic field with a magnitude of 2.00 mT. The angular momentum of the electron about the center of the circle is 3.50 *10^-25 J·s. - AnswerMenu

An electron moves in a circular path perpendicular to a constant magnetic field with a magnitude of 2.00 mT. The angular momentum of the electron about the center of the circle is 3.50 *10^-25 J·s.

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An electron moves in a circular path perpendicular to a constant magnetic field with a magnitude of 2.00 mT. The angular momentum of the electron about the center of the circle is 3.50 10^{-25} J·s.

(a) Determine the radius of the circular path. cm
(b) Determine the speed of the electron. m/s