A flat surface of area 2.60 m^2 is rotated in a uniform electric field of magnitude E = 6.35 * 10^5 N/C.

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A flat surface of area 2.60 m2 is rotated in a uniform electric field of magnitude E = 6.35 image 105 N/C.

(a) Determine the electric flux through this area when the electric field is perpendicular to the surface.
 N · m2/C

(b) Determine the electric flux through this area when the electric field is parallel to the surface.
 N · m2/C
asked Feb 10, 2012 in Physics by awesome ~Expert~ (1,479 points)
    

1 Answer

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Best answer

The formula for electric flux is as follows:

Electric flux = E*A (* E = electric field, A = area)

and if electric flux is at an angle from the normal (which is perpendicular) the formula is:

Electric flux = E*A*cos(theta)   (* E = electric field, A = area, theta = angle between the normal of E and A)

 

So for part A, the field is perpendicular so we use the first formula.

Electric flux = E*A

E =  6.35 image 105 N/C

A = 2.60 m2  

Now plug in the values into the formula.

 

Electric flux = 6.35 image 105 N/C  *   2.60 m   =    1651000 N · m2/C 

Electric flux = 1651000 N · m2/C 

 

Part B, the electric field is parallel, so it is at an angle of 90 from the normal.

So use the second formula:

Electric flux = E*A*cos(theta) 

 

cos(90) = 0,

so therefore the electric flux will be 0.

Electric flux = 0

answered Feb 14, 2012 by kirby ~Expert~ (3,020 points)
selected Feb 15, 2012 by awesome

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