A proton beam in an accelerator carries a current of 123 µA. If the beam is incident on a target, how many protons strike the target in a period of 29.0 s?

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A proton beam in an accelerator carries a current of 123 µA. If the beam is incident on a target, how many protons strike the target in a period of 29.0 s?


protons

asked Feb 2, 2012 in Physics by yoshi ~Expert~ (919 points)
    

1 Answer

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Best answer

The formula for current is:

i = dq/dt  (where i=current, q=charge, t=time)

the values given in the equation are:

i = 123 µA = 123*10^-6 A

t = 29s

 

substituting in the the equation for i we get:

123*10^-6 A = q / 29s

So solving for q:

q = 123*10^-6 A * 29s =0.003567 C

Now that we know the charge we can find the number of protons by dividing the charge by the charge of one proton.

charge of 1 proton = 1.602*10^-19C

Number of protons = 0.003567 C / 1.602*10^-19C  = 2.23*10^16 protons

 

2.23*10^16 protons strike the target in 29s

 

answered Feb 2, 2012 by pokemonmaster ~Expert~ (3,856 points)
selected Feb 2, 2012 by yoshi

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