Since the object is moving at a constant speed, we assume there is no acceleration, therefore

**Total Force = mass*acceleration**

Total Force =mass*0

Total Force = 0

**Frictional force = 7.38 N**

Total Force = Force - Frictional Force = 0

so

Force = Frictional Force

**Force = 7.38 N**

To find work we use the following formula:

**Work = Force * distance**

**Part A:**

Using the coordinates given, we realize that the distance from O to A is 5 m, since the object goes from O to A and then back to O, we multiply 5 by 2, and get 10 m for the total distance (net displacement) traveled in part A.

**distance = 10 m**

Work = **7.38 N * 10m = 73.8 J**

**Part B.**

First find the net displacement (total distance traveled.)

The purple path from O to C is 10 m. And the return blue path can be found using the pythageoreom theorem:

a^2+b^2=c^2

√(25m+25m) = c

c=7m

Therefore the net displacement is 5m + 5m + 7m = 17m

Plugging this into the work equation we get:

**Work = 7.38 N* 17m = 125.46 J**

**Part C** is also solved the same way.

**Work = 7.38 N * 14 m**

Part D: We learn that the force of friction is a **nonconservative **force, because the values are nonzero.