When a battery is connected to the plates of a 4.00-µF capacitor, it stores a charge of 96.0 µC. What is the voltage of the battery?

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(a) When a battery is connected to the plates of a 4.00-µF capacitor, it stores a charge of 96.0 µC. What is the voltage of the battery?
V

(b) If the same capacitor is connected to another battery and 36.0 µC of charge is stored on the capacitor, what is the voltage of the battery?
V

asked Jan 27, 2012 in Physics by Roar3215 ~Expert~ (1,318 points)
    

1 Answer

+2 votes
 
Best answer

The formula for Capacitance is:

C = Q / V  (where Q = charge, and V = voltage)

Rearrange, the equation so you are solving for V.

V = Q / C

Now plug in your values, Q = 96 µC and C = 4 µF  (*since they are both in µ there is no need to convert to SI units, since the units will cancel out, and result in just Volts)

and so:

V = 96 µC / 4 µF = 24 V

 

Similarly for Part B just, replace Q with 36 µC and plug in the equation once more,

 

V = 36 µC / 4 µF = 9 V

answered Jan 28, 2012 by pokemonmaster ~Expert~ (3,856 points)
selected Jan 28, 2012 by Roar3215



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