Three positive charges are located at the corners of an equilateral triangle as in the figure below. Find an expression for the electric potential at the center of the triangle. (Use the following as necessary: *k*_{e}, *Q*, and *d*.)

*V* =

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Best answer

The voltage potential for the system can be found with the following equation:

**V = ke * (q1/r1 + q2/r2)**

Using the geometry of the triangle, you can conclude that the distance of the charges to the center of the triangle is **d / squareroot(3)**

**radius = d/sqrt(3)**

plugging this and the value of Q into the first equation we get:

**V = ke * [Q/(****d/sqrt(3))****+ Q/(****d/sqrt(3)) + 2Q/(****d/sqrt(3))]**

**V = (ke*Q / d) * 4*sqrt(3)**

**Final Answer**

**V = 6.93 (ke*Q / d)**

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