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Find an expression for the electric potential at the center of the triangle

+6 votes

Three positive charges are located at the corners of an equilateral triangle as in the figure below. Find an expression for the electric potential at the center of the triangle. (Use the following as necessary: ke, Q, and d.)
V =

image
asked Jan 20, 2012 in Physics by awesome ~Expert~ (1,473 points)
    

1 Answer

+4 votes
 
Best answer

The voltage potential for the system can be found with the following equation:
 

V = ke * (q1/r1 + q2/r2)

Using the geometry of the triangle, you can conclude that the distance of the charges to the center of the triangle is  d / squareroot(3)

radius = d/sqrt(3)

plugging this and the value of Q into the first equation we get:


V = ke * [Q/(d/sqrt(3))+ Q/(d/sqrt(3)) + 2Q/(d/sqrt(3))]

V = (ke*Q / d) * 4*sqrt(3)

 

Final Answer

V = 6.93 (ke*Q / d)

answered May 22, 2012 by pokemonmaster ~Expert~ (3,847 points)
selected May 23, 2012 by awesome

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