Simplify 4*√12 + 3*√48?

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asked Dec 23, 2012 in Mathematics by anonymous
    

1 Answer

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4*√12 + 3*√48

simplifying the radicals, we get:


= 4*(√4)*(√3) + 3*(√4)*(√12)
 

the second of which can be further broken down

= 8*√3 + 6*√12


= 8*√3 + 6*(√4)*(√3) 


= 8*√3 + 12*√3


= (√3)*[8 + 12]

therefore you get:


= 20*√3

answered Dec 23, 2012 by anonymous

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