In the Bohr theory of the hydrogen atom, an electron moves in a circular orbit about a proton

+3 votes

In the Bohr theory of the hydrogen atom, an electron moves in a circular orbit about a proton, assume the radius of the orbit is

5.29 image 10-11 m.
(a) Find the magnitude of the electric force exerted on each particle.
N

(b) If this force causes the centripetal acceleration of the electron, what is the speed of the electron?
m/s

 

asked Jan 15, 2012 in Physics by Joey33 ~Expert~ (1,216 points)
    

1 Answer

+2 votes

F = (ke * e^2) / r^2

ke = 8.99*10^9 N*m^2 / C^2

e = 1.60*10^-19 C

r = 5.29*10^-11 m

So F = 8.22*10^-8 N

 

 

Part B:

centripetal acceleration = v^2 / r

F=ma, so a = F/m

hence. F/m = v^2 / r

and so v = (F*r/m)^1/2

now plug in the values:

F = 8.22*10^-8 N

r = 5.29*10^-11 m

m = 9.11*10 ^-31 kg

and the result is:

v = 2.19*10^6 m/s

 

answered Jan 20, 2012 by awesome ~Expert~ (1,479 points)
edited Jan 20, 2012 by awesome



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