Three point charges lie along a straight line as shown in the figure below

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Three point charges lie along a straight line as shown in the figure below, where
q1 = 6.54 µC, q2 = 1.56 µC, and q3 = -1.98 µC. The separation distances are d1 = 3.00 cm and d2 = 2.00 cm. Calculate the magnitude and direction of the net electric force on each of the charges.
image
(a) q1
magnitude N
direction  

(b) q2
magnitude N
direction  

(c) q3
magnitude N
direction
   

 

asked Jan 15, 2012 in Physics by Roar3215 ~Expert~ (1,298 points)
    

1 Answer

+3 votes
 
Best answer
To calculate the net electric force on each of the charges this is what you do:

For Part A: The force acting on charge 1 is as follows,

F1 = F21 + F31, (in other words the force acting on charge 1 is equal the force of charge 2 on 1, plus the force of charge 3 on 1)

After establishing this you go on to use the Electric Force Equation, which is:

F=(ke * q1*q2)/ r^2

where ke=8.988*10^9 N*m^2/C^2

and r is the distance between the two charges.

Do not forget to first conver the units of the charge and distance to the proper SI units of Coulomb and meter.

 

The direction can be determined based on the diagram, if two charges are alike then the force would point towards the other force, and if the charge are not alike then the force would point towards itself.
answered Jan 17, 2012 by kirby ~Expert~ (3,015 points)
selected Jan 17, 2012 by pokemonmaster
So then how would you be able to find the force on q2?

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