# algebra . i need help please and thank you

+1 vote
determine the zeros of the function 3x^2-8=10x
asked Jan 8, 2012 in Algebra

Determining the zeros mean you will need to set the equation equal to zero and then solve for  x. so first rewrite it in the form ax^2+bx+c,

1. resulting in 3x^2-10x-8

2. Now apply the quadratic formula:

$x=\frac{-b \pm \sqrt {b^2-4ac}}{2a},$

with a=3, b=-10, and c=-8

if you need more help in solving, please comment, good luck!

answered Jan 8, 2012 by ~Expert~ (3,856 points)
edited Jan 8, 2012
Yep that looks right.
thank you!
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