algebra . i need help please and thank you

+1 vote
determine the zeros of the function 3x^2-8=10x
asked Jan 8, 2012 in Algebra by Jordant94 (39 points)
    

1 Answer

0 votes

Determining the zeros mean you will need to set the equation equal to zero and then solve for  x. so first rewrite it in the form ax^2+bx+c,

1. resulting in 3x^2-10x-8

2. Now apply the quadratic formula:

x=\frac{-b \pm \sqrt {b^2-4ac}}{2a},
 
 
with a=3, b=-10, and c=-8
 
if you need more help in solving, please comment, good luck!
 
 
answered Jan 8, 2012 by pokemonmaster ~Expert~ (3,856 points)
edited Jan 8, 2012 by pokemonmaster
Yep that looks right.
thank you!
You're Welcome! If you have any more questions please post here.

Related questions

+2 votes
1 answer 274 views
+1 vote
3 answers 145 views
145 views asked Jan 8, 2012 in Algebra by Jordant94 (39 points)
0 votes
1 answer 49 views
49 views asked Jan 5, 2012 in Algebra by sammy.sam187485 (37 points)
+1 vote
1 answer 62 views
62 views asked Jan 5, 2012 in Mathematics by sammy.sam187485 (37 points)
+1 vote
2 answers 53 views
53 views asked Jan 3, 2012 in Science by anonymous



...